Question

Help me please....

Ans fast plz..

Prove that
$\frac{1 - \tan \alpha }{1 + \tan\alpha } = { \cos}^{2} \alpha - { \sin }^{2} \alpha$

Answer 1

Hey !!!

This is too simple .

From RHS .

cos²@ - sin²@

= cos²@ - sin²@ /1 [we can write 1 as denominator]

= cos²@- sin²@/sin²@ + cos²@

[•°•sin²¢ + cos²¢ = 1 so we can write at place of 1 ]

= cos²@ - sin²@/cos²@
------------------------------- ..
sin²@ + cos²@ /cos²@
{dividing by cos²@ on numerator and denominator}

then we get ,

1 - tan²@
-------------= LHS prooved
1 + tan²@

I think ur question is little bit wrong

it should be 1 - tan²@/1+ tan²@ = cos²A- sin²@ proove it

**************************************************

Hope it helps you !!!

@Rajukumar111

Answer 2

Answer:

hope it helps