Math, asked by banditapattnaik, 7 months ago

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Answered by Anonymous
1

Solution:-

The given equation is :-

=> x²+y²+4x-20y+100=0

This is of the form of

=> x²+y²+2gx+2fy+c=0

Where

2g=4 ,2f= -20 and c=100

Now , we get :-

g=2 , f= -10 and c= 100

Hence, the given equation represent a circle

Centre of circle is =(-g,-f)=(-2,10)

Radius of the circle is

 \sqrt{g {}^{2}  +  {f}^{2} - c }

 \sqrt{(2) {}^{2}  + ( - 10) {}^{2} - 100 }

 \sqrt{4 + 100 - 100}

 \sqrt{4}  = 2

Radius=2 unit

i) Circumference of circle is=

2\pi \: r

R= 2 units

c = 2 \times  \frac{22}{7}  \times 2

c =  \frac{88}{7}

c = 12.57 \: unit

ii) Area of circle is

\pi \:  {r}^{2}

R=2, so we get

 \frac{22}{7}  \times 2 \times 2

Area of circle is 12.57 unit

Answer:-(i) Center=(-2,10)

(ii) Radius=2 units

(iii) Area=12.57 units

(iv)Circumference =12.57units

Answered by renuthakur3333
5

Answer:

Area of circle is 12.57 unit

Answer:-(i) Center=(-2,10)

(ii) Radius=2 units

(iii) Area=12.57 units

(iv)Circumference =12.57units

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