Question

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Answer 1

Answer:

Given :

Initial velocity , u = 30m/s

Force = 1500 N

Time , t = 2 sec

To find :

The change in momentum and the retardation in car .

Solution :

Using the first equation of motion ,

v = u - at

where , v is final velocity ,

minus sign for retardation .

putting the values ,

0 = 30 - a * 2

a = 15 m/

now,

force = 1500 N

m * a = 1500 N

m = 100 kg

change in momentum of car = m ( v - u )

                                              = 100 (-30)

                                              = - 3000 kg m /s

The reatardation is 15m/ and the change in momentum is - 3000 kg m /s

Explanation:  

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Answer 2

Answer:

u=30m/s

t=2s

v=0

f=-1500N (since it is a retarding force)

we know a=(v-u)/t

=0-30/2

=-30/2

=-15 m/s²

So,

c) f=ma

-1500=m×(-15)

m=-1500/-15

=100 kg

b) r=-a

so, r=-(-15)

=15m/s²

a) initial momentum=mu=100×30

=3000 kg m/s

final momentum=mv=100×0

=0 kg m/s

change in p=mv-mu

=0-3000=3000 kg m/s

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