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Initial potential energy = mgh = 10x103x9.8x5 = 0.49 J
when it jus before striking the ground all the initial
potential energy is converted into kinetic energy.
Hence kinetic energy just before striking the ground =
0.49 J
when it rebounds to height 4 m, its final potential energy =
10x10-3x9.8x4 = 0.392 J
Kinetic energy after striking the ground is converted into
final potential energy at 4 m height
Hence kinetic energy after striking the ground 0.392 J
loss in kinetic energy = 0.49- 0.392 = 0.1 J
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Answer:
Initial potential energy = mgh = 10x103x9.8x5 = 0.49 J
when it jus before striking the ground all the initial
potential energy is converted into kinetic energy.
Hence kinetic energy just before striking the ground =
0.49 J
when it rebounds to height 4 m, its final potential energy =
10x10-3x9.8x4 = 0.392 J
Kinetic energy after striking the ground is converted into
final potential energy at 4 m height
Hence kinetic energy after striking the ground 0.392 J
loss in kinetic energy = 0.49- 0.392 = 0.1 J
Explanation:
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