Question

help me please can't understand​

Answer 1

Answer:

see picture.....

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Answer 2

We have equations,

3x + 4y = 5

9/2x - 6y = 15/2

Take a1 = 3, b1 = 4, c1 = -5

a2 = 9/2, b2 = -6, c1 = -15/2

a1/a2 = 3 ÷ 9/2 = 3 × 2/9 = 2/3

b1/b2 = 4/-6 = -2/3

c1/c2 = -5 ÷ -15/2 = -5 × -2/15 = 2/3

From this we can conclude that,

a1/a2 ≠ b1/b2 = c1/c2

Or

a1/a2 ≠ b1/b2

Hence, It is an unique solution.

Answer: (a) Unique solution

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