Help me PLEASE!! I WILL MARK BRAINLIEST
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Answer:
hey mate here is your answer
Step-by-step explanation:
Given, AC=AE
AB=AD
/_BAD = /_EAC
we need to prove : BC=DE
proof:- /_ BAD =/_EAC
=> /_BAD + /_DAC = /_EAC+ /_DAC
.•./_BAC=/_DAC. ________(1)
in ∆ABC and ∆ADE,
AB =AD (given)
/_BAC =/_DAC (from 1)
AC=AE (given)
from SAS CONGRUENCE RULE we have ,
∆ABC=~ ∆ADE
.•. BC=DE
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