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Answers
Step-by-step explanation:
Solutions:-
1)
Let the number should be multiplied be X
Given number = 9 4/5
=> (9×5+4)/5
=> (45+4)/5
=> 49/5
On multiplying 49/5 with X then the result
= (49/5)×X
= 49X/5
According to the given problem
The result = 42
=> 49X/5 = 42
=> 49X = 42×5
=> 49X = 210
=> X = 210/49
=> X = 30/7
=>X = 4 2/7
Answer :-
The required number is 30/7 or 4 2/7
Check:-
On multiplying 4 9/5 with 4 2/7
=> 4 9/5 × 4 2/7
=> (49/5)×(30/7)
=> (49×30)/(5×7)
=> 7×6
=> 42
Verified the given relations in the given problem
2)
Let the number should be duvided be X
Given number = 6 2/9
=> (6×9+2)/9
=> (54+2)/9
=> 56/9
On dividing 56/9 by X then the result
= (56/9)/X
= 56/9X
According to the given problem
The result = 4 2/3 = 14/3
=> 56/9X = 14/3
=> 9X×14 = 56×3
=> 9X = 56×3/14
=> 9X = 4×3
=>9X = 12
=>X = 12/9
=>X = 4/3 or 1 1/3
Answer :-
The required number is 4/3 or 1 1/3
Check:-
On dividing 6 2/9 by 1 1/3
=> 6 2/9 ÷ 1 1/3
=> (56/9)÷(4/3)
=> (56/9)×(3/4)
=> (56×3)/(9×4)
=> 14/3
=> 4 2/3
Verified the given relations in the given
Answer:
1)let assume the no. - x
x×94/5=42
x=42×5/94
x=21×5/47
x=105/47
2)=6(2/9)
=4(2/3)
=18/54
=8/12
=18/54
=18/12
hence both are equal