Help me please....
*Q. is attached*
*Please give correct ans.*
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1.
(i) It has two zeroes as the parabola touches two points of x - axis,
They are - zeroes - (-2), 0 and so it is a quadratic polynomial as there are 2
zeroes.
Quadratic Polynomial: x² - (sum of zeroes)x + product of zeroes
Sum of zeroes = -2 + 0 ⇒ -2
Product of zeroes = -2(0) ⇒ 0
Quadratic Polynomial = x² - (-2)x + (0)
= x² + 2x + 0
0 = x² + 2x
________________________________________________________
(ii) Even though it touches one point on x-axis, it must be linear equation. But
since linear equation forms straight lines in graph, this contradicts here as the
line is curved.
So it is neither linear nor quadratic for the same
_________________________________________________________
☺ ☺ ☺ Hope this Helps ☺ ☺ ☺
(i) It has two zeroes as the parabola touches two points of x - axis,
They are - zeroes - (-2), 0 and so it is a quadratic polynomial as there are 2
zeroes.
Quadratic Polynomial: x² - (sum of zeroes)x + product of zeroes
Sum of zeroes = -2 + 0 ⇒ -2
Product of zeroes = -2(0) ⇒ 0
Quadratic Polynomial = x² - (-2)x + (0)
= x² + 2x + 0
0 = x² + 2x
________________________________________________________
(ii) Even though it touches one point on x-axis, it must be linear equation. But
since linear equation forms straight lines in graph, this contradicts here as the
line is curved.
So it is neither linear nor quadratic for the same
_________________________________________________________
☺ ☺ ☺ Hope this Helps ☺ ☺ ☺
Shatakshi96:
the polynomial of this cubic polynomial will be y = x³ - 1
Fine....
edit ur ans.
Hm...
But I am not sure of this and I am not going to edit this
But I am not sure of this(ur ans)
I'm sure about my answer.. this is correct
u can even put the values and see ur self
if u find it as most helpful pls mark it as brainliest
TQ for Brainliest sis
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