Question

help me please question from maths class 11​

Answer 1

Answer:

Step-by-step explanation:

d/dx (tanx-cotx)

= d(tanx)/dx - d(cotx)/dx

= sec²x- (-cosec²x)

= sec²x+cosec²x

Answer 2

Answer:

$\bf =\sec^2x+cosec^2\ x$

Step-by-step explanation:

$\frac{d}{dx} ( \tan x -\cot x)\\\\=\frac{d}{dx} ( \tan x) -\frac{d}{dx} ( \cot x)\\\\=\sec^2x- ( - cosec^2x)\\\\\bf =\sec^2x+cosec^2\ x$