Help me please to solve this question
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Refer to an attachment to get a clear idea.
- we can solve this math puzzle by using the fundamental method of problem-solving ''Trial and Error''.
- we need to fill the given grid by using 1-9 digits without repeating the same digits.
- In this math puzzle question, normal mathematical operations(DMAS) are ignored.
Now, let's find out how the grid is solved:
It is given the middle number is 8, we know that 6 times 8 = 48.
Middle row will be: 6 x 8 x 1 = 48
Middle column: first, I am taking half of 80 = 40.
so, we know that 5 times 8 = 40
Now, we know that two times 40 is 80.
Middle column will be: 2 x 8 x 5 = 80.
we are done with the numbers: 1, 2, 5, 6, and 8.
We need to fill the remaining gaps by using the method of 'Trial and Error' with the numbers 3, 4, 7, and 9.
Now, First row will be: 3 + 2 x 4 = 20
First column will be: 3 + 6 - 9 = 0
Last column will be: 4 - 1 + 7 = 10
Last row will be: 9 x 5 - 7 = 38
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