Math, asked by srivastavaanushka896, 2 months ago

Help me please with the question.​

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Answered by NITESH761
2

Answer:

\rm \sqrt{32}

Step-by-step explanation:

In an isosceles right triangle both base and height are equal,

so, area of the triangle is,

\rm \dfrac{1}{2}×s×s

where s is equal sides,

\rm 8=\dfrac{s^2}{2}

\rm s^2=8×2

\rm s = \sqrt{16}

\rm s = 4

by Pythagoras theorem,

\rm hypotenuse= \sqrt{4^2+4^2}

\rm = \sqrt{32}

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