help me please with these three questions of chemistry
please
Attachments:
Answers
Answered by
1
3. a) Copper dissolves in acids (acidic solutions) and becomes Cu⁺² ions.
b) Put a metal more reactive and electropositive than Copper into the solution. Then Copper precipitates and The other metals become ions. Examples : Magnesium, Potassium etc.
4. Caustic soda or Sodium Hydroxide Na OH dissolves in water or becomes a liquid when fused (heated). So then Sodium and Hydroxide exist as ions. Because they get liberated from the rigid crystal structure in the solid form.
As these ions Na⁺ and OH⁻ are able to move in a liquid, they flow towards the anode and cathode. That constitutes electric current as charges flow.
Similarity is that in both cases the ions flow and reach the electrodes. Sodium gets deposited and Hydrogen gets released. It is similar to electrolysis.
5. a) H2 SO4 (aq) solution with Platinum electrodes.
Two types of anions with negative charges: SO₄⁻² and OH⁻.
SO4 comes from the acid. OH- comes from water.
b) O2 gas is discharged from the anode. SO4⁻² ion is very stable. So it does not split. But,
4 OH⁻ (aq) - 4 e⁻ ===> 2 H₂O + O₂ (g)
The additional electrons in OH- ion reach the anode and flow into the circuit.
c) At the cathode, H2 gas is released. The electrons from anode reach the cathode and are taken in by Hydrogen ions from the acid/water.
4 H⁺ (aq) + 4 e⁻ ==> 2 H₂ (g)
d) Color changes due to SO₄⁻² ions. Perhaps blue or green.
e) Catalysis is a reaction taking place in presence of a catalyst. The presence increases or decreases the rate of reaction. The catalyst stays as it is OR, it is regained after some intermediate reactions.
Here H₂SO₄ is a catalyst. Water is getting electrolysed. Ions of Sulphuric acid stay in the solution.
b) Put a metal more reactive and electropositive than Copper into the solution. Then Copper precipitates and The other metals become ions. Examples : Magnesium, Potassium etc.
4. Caustic soda or Sodium Hydroxide Na OH dissolves in water or becomes a liquid when fused (heated). So then Sodium and Hydroxide exist as ions. Because they get liberated from the rigid crystal structure in the solid form.
As these ions Na⁺ and OH⁻ are able to move in a liquid, they flow towards the anode and cathode. That constitutes electric current as charges flow.
Similarity is that in both cases the ions flow and reach the electrodes. Sodium gets deposited and Hydrogen gets released. It is similar to electrolysis.
5. a) H2 SO4 (aq) solution with Platinum electrodes.
Two types of anions with negative charges: SO₄⁻² and OH⁻.
SO4 comes from the acid. OH- comes from water.
b) O2 gas is discharged from the anode. SO4⁻² ion is very stable. So it does not split. But,
4 OH⁻ (aq) - 4 e⁻ ===> 2 H₂O + O₂ (g)
The additional electrons in OH- ion reach the anode and flow into the circuit.
c) At the cathode, H2 gas is released. The electrons from anode reach the cathode and are taken in by Hydrogen ions from the acid/water.
4 H⁺ (aq) + 4 e⁻ ==> 2 H₂ (g)
d) Color changes due to SO₄⁻² ions. Perhaps blue or green.
e) Catalysis is a reaction taking place in presence of a catalyst. The presence increases or decreases the rate of reaction. The catalyst stays as it is OR, it is regained after some intermediate reactions.
Here H₂SO₄ is a catalyst. Water is getting electrolysed. Ions of Sulphuric acid stay in the solution.
kvnmurty:
:-) :-)
Similar questions