Question

help me __pls answer with explanation_ i will mark as brainiest☆.☆​

Answer 1

Answer:

this is correct ans

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Answer 2

Let p(x) =x

3

+6x

2

+11x+6

Put x=–1

p(–1) =(–1)

3

+6(–1)

2

+11(–1)+6=–1+6–11+6=0

∴(x+1) is a factor of p(x)

So, we cam break up terms of p(x) as follows.

p(x)=x

3

+6x

2

+11x+6

Therefore, the integral roots of the given equation is find out as:

p(x)=0

(x+1)(x+2)(x+3)=0

x=−1,−2,−3

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