Question

help me pls????? asap​

Answer 1

(100x+10y+z) + (100x+10y+z) + (100x+10y+z) = 100z + 10z +z

3(100x+10y+z) = 3(111)z

100x+10y+z = 111z

100x + 10y = 110z

10x +y = 11z

By elimination, z must be equal to 5, as only 5*3 gives a number with unit digit 5.

y + y +y +1 = number with unit digit 5

Only number divisible by three that gives unit digit 5 when 1 is added is 8

Thus y=8

x + x +x +2(as 2 is carried over) = 5

3x + 2 = 5

3x = 3

X = 1

Thus the digits are

x = 1

y = 8

z = 5