Question

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Answer 1

Answer:

3.6x10³ V

Explanation:

potential at any point inside the surface of spherical conductor is equal to the potential on surface of sphere

k=9x10⁹Nm²/C²,q=2x10-⁶C , r=5m

V=kq/r

V=9x10⁹x2x10-⁶/5

V=18x10³/5

V=3.6x10³volt