Math, asked by Sadmath, 1 month ago

Help me pls. I can’t think of an answer

Attachments:

Answers

Answered by dassrijani1610
3

Answer:

B = 1

Step by step explanation

we can write A B as A×10 + B × 1

since B + B = A (in ones place)

2B = A

and in tens place ,

A + C = B

2B + C = B

C = -2B + B

C = -B

Now , we can rearrange the given question as

2B B

+ -B B

-----------

B 2B

Therefore we can consider the value of B as 1

proof :-

A = 2B = 2×1 = 2

B = 1

C = -B = -1

putting these values to question you can get that

Answered by kv44489
2

Answer:

you can supposed any value for B

but you need to prove the value of B

I proved the value of B

the statement given below

B + B = A ( In one's place)

=> 2B = A => A > B

• A + C = 2B + C = B ( In ten's place)

=> C = -2B + B

=> C = -B

=> B = - C => B > C

(B is a positive number and -C is a negative numbers)

  • Every postive numbers greater than every negative numbers

let take a number 4 as example and apply the number on each statement.

A > B > -C

Largest number = A = 4

Value of B

=> A = 2B

=> 2B = 4

=> B = 4/2 = 2

=> B = 2

Value of C

=> C = -B

=> C = -2

Time to prove my statement :-

A B = A × 10 + B × 1 = 40 + 2 = 42

C B = C × 10 + B × 1 = -20 + 2 = -18

A B + C B = B A ( Given in figure )

42 + ( -18 ) = B A

42 - 18 = 24

24 = B A

2 × 10 + 4 × 1 = B × 10 + A × 1

( B = 2 and A = 4 )

20 + 4 = 2 × 10 + 4 × 1

24 = 20 + 4

24 = 24

hence it's proved

I hope it's help you please mark me as brainlist and give some thanks

I solve with this question with myself not paste from internet

Similar questions