Question

help me pls

IN THE GIVEN FIGURE, L IS THE MIDPOINT OF AB, AB IS A CHORD. PROVE THAT OL IS THE PERPENDICULAR TO AB​

Answer 1

let the point O be the midpoint of the circle

let the point O be the midpoint of the circleif O is midpoint of the circle then , by the properties of circle . the chord = the radius of the circle

let the point O be the midpoint of the circleif O is midpoint of the circle then , by the properties of circle . the chord = the radius of the circle I hope it helped you

plz mark as brainlist

Answer 2

Given, AL = LB (L is the midpoint of AB)

OA = OB (Radii of same circle)

OL is common side

So, ∆AOL is congruent to ∆OBL

hence, angle ALO = angle BLO (C.P.C.T.)

now, angle ALO + angle BLO = 180° (linear pair)

Since, angle ALO = angle BLO and their sum is 180°, so to satisfy the conditions, angle ALO and angle BLO both will be equal to 90°

Now, if angle ALO = 90° and angle BLO = 90°, then it means OL is perpendicular on AB (since a perpendicular makes an angle of 90° on both sides with a base line)