Question

HELP ME PLSSSSSSSSSSSS

Answer 1

Answer:

$\large{\underline{\underline{\bf{\purple{Question \: : - }}}}}$

$\begin{gathered}\\ \dashrightarrow{\sf{3\dfrac{1}{5}} + 75\% - {1\dfrac{3}{10}}} \end{gathered}$

$\begin{gathered}\end{gathered}$

$\large{\underline{\underline{\bf{\purple{Solution\: : - }}}}}$

$\begin{gathered}\\ \dashrightarrow{\sf{3\dfrac{1}{5}} + 75\% - {1\dfrac{3}{10}}} \\ \end{gathered}$

$\red \divideontimes$ Firstly, converting mixed fractions into improper fraction.

$\begin{gathered} \\ {\dashrightarrow{\sf{\dfrac{(3 \times 5) + 1}{5}} + 75\% - {\dfrac{(1 \times 10) + 3}{10}}}} \\ \end{gathered}$

$\begin{gathered}{\dashrightarrow{\sf{\dfrac{15 + 1}{5}} + 75\% - {\dfrac{10 + 3}{10}}}} \\ \end{gathered}$

$\begin{gathered}{\dashrightarrow{\sf{\dfrac{16}{5}} + 75\% - {\dfrac{13}{10}}}} \\ \end{gathered}$

$\red \divideontimes$ As we know that, 1% = 1/100, then converting 75% into improper fraction.

$\begin{gathered}\\{\dashrightarrow{\sf{\dfrac{16}{5}} + \dfrac{75}{100} - {\dfrac{13}{10}}}} \\ \end{gathered}$

$\red \divideontimes$ According to the BODMAS, Firstly we will perform the addition.

$\begin{gathered}\\{\dashrightarrow{\sf{\bigg(\dfrac{16}{5}} + \dfrac{75}{100} \bigg) - {\dfrac{13}{10}}}} \\ \end{gathered}$

$\red \divideontimes$ Taking the LCM of denominators.

$\begin{gathered}\\{\dashrightarrow{\sf{\bigg(\dfrac{(16 \times 20) + (75 \times 1)}{100}} \bigg) - {\dfrac{13}{10}}}} \\ \end{gathered}$

$\begin{gathered}{\dashrightarrow{\sf{\bigg(\dfrac{320 + 75 }{100}} \bigg) - {\dfrac{13}{10}}}} \\ \end{gathered}$

$\begin{gathered}{\dashrightarrow{\sf{\bigg(\dfrac{395 }{100}} \bigg) - {\dfrac{13}{10}}}} \\ \end{gathered}$

$\red \divideontimes$ Now, converting 395/100 in simplest form.

$\begin{gathered}\\ {\dashrightarrow{\sf{\bigg( \cancel{\dfrac{395 }{100}}} \bigg) - {\dfrac{13}{10}}}} \\ \end{gathered}$

$\begin{gathered}{\dashrightarrow{\sf{\bigg(\dfrac{79}{20}} \bigg) - {\dfrac{13}{10}}}} \\ \end{gathered}$

$\red \divideontimes$ Now, performing subtraction, according to BODMAS.

$\begin{gathered}\\ {\dashrightarrow{\sf{\dfrac{79}{20}} - {\dfrac{13}{10}}}} \\ \end{gathered}$

$\red \divideontimes$ Again, taking LCM of denominators.

$\begin{gathered}\\ {\dashrightarrow{\sf{\dfrac{(79 \times 1) - (13 \times 2)}{20}}}} \\ \end{gathered}$

$\begin{gathered}{\dashrightarrow{\sf{\dfrac{79 -26}{20}}}} \\ \end{gathered}$

$\begin{gathered}{\dashrightarrow{\sf{\dfrac{53}{20}}}} \\ \end{gathered}$

$\begin{gathered}\red{\bigstar{\underline{\boxed{\bf{Answer = \dfrac{53}{20}}}}}}\end{gathered}$

∴ The answer is 53/20.

$\begin{gathered}\end{gathered}$

$\large{\underline{\underline{\bf{\purple{Learn \: More\: : - }}}}}$

$\underline{\underline{\pmb{\mathbb{\red{BODMAS \: :}}}}}$

BODMAS rule is an acronym used to remember the order of operations to be followed while solving expressions in mathematics.

It stands for :-

• ↠ B - Brackets,
• ↠ O - Order of powers or roots,
• ↠ D - Division,
• ↠ M - Multiplication 
• ↠ A - Addition,
• ↠ S - Subtraction.

It means that expressions having multiple operators need to be simplified from left to right in this order only.

$\rule{200}2$

$\underline{\underline{\pmb{\mathbb{\red{BODMAS \: RULE \: :}}}}}$

First, we solve brackets, then powers or roots, then division or multiplication (whatever comes first from the left side of the expression), and then at last subtraction or addition.

• ↠ Addition (+)
• ↠ Subtraction (-)
• ↠ Multiplication (×)
• ↠ Division (÷)
• ↠ Brackets ( )

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