Question

HELP ME PLZ........


I'LL MARK YOU AS A BRAINLIEST

Answer 1

let radius of one circle is x and of other circlr is y

so, x +y =14

also, pi*x^2 +pi*y^2 = 130*pi

so, x^2 + y^2 = 130

squaring x+y =14 on both sides, we get

x^2 + y^2 +2xy = 196

=> 130+2xy = 196

2xy = 66

so, (x-y)^2 = x^2 + y^2 -2xy = 130-66 =64

so, x-y =8 ( by taking square root on both sides)

Now, x+y =14..(i)

and x-y =8....(ii)

Adding (i) and (ii)

2x =22

x=11

so, y =3

Answer 2

Answer:

Step-by-step explanation:

Let the radius of two circles be R andr

Area of a circle is πr²

It is given that

πR²+πr²=130π

π(R²+r²)=130π

R²+r²=130 ------------1

Distance between radius is 14cm

It means that R+r=14cm -----------2

R²+r²=(R+r)²-2Rr

[(a+b)²=a²+b²+2ab]

[So,a²+b²=(a+b)²-2ab]

Put value of this in 1

(R+r)²-2Rr=130

(14) ²-2Rr=130 -------[from2]

196 -2Rr=130

-2Rr=130-196

-2Rr=-66

Rr=-66/-2

Rr=33

R=33/r

Put value of R in 2

33/r+r=14

Taking LCM and cross multiplication we get

33+r²=14r

r²-14r+33=0

r²-11r-3r+33=0

r(r-11)-3(r-11)=0

(r-3)(r-11)=0

r-3=0 r-11=0

r=3 r=11

Radius of one circle is 3cm and radius of other is 11cm

Hope it will help you

Thanks