Question

Help me.plz
it's very urgent​

Answer 1

Answer:

its second one

Step-by-step explanation:

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Answer 2

C has a 'Terminating decimal expansion'

$c = \frac{1}{2 ^{3000} } \\ {2}^{3000} = {2}^{3000} \times {5}^{0} \\ = {2}^{n} \times {5}^{m}$

Since the denominator of C is of the form 2^n×5^m

Therefore it has a terminating decimal expansion.