Physics, asked by Anonymous, 1 year ago

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Plz gimmi the derivation of compound microscope...

Answers

Answered by himanshupassey26
1

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Answered by NehaKari
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Magnification of compound microscope is: M = (FD/FE) x (OA/OB).

To find:

Derivation of compound microscope

Given:

  • Consider a simple compound microscope consisting of an objective lens O and an eyepiece lens E.
  • The object AB is placed at a distance u from the objective lens.
  • The image of the object is formed by the objective lens at a distance v1 from it.
  • The eyepiece lens forms a final image A'B' at a distance v2 from it, which is observed by the observer's eye.

Solution:

The magnification of the objective lens is given by the formula:

M1 = -v1/u

The magnification of the eyepiece lens is given by the formula:

M2 = -v2/f

f is  focal length of eyepiece lens.

The total magnification of the compound microscope is given by the product of the magnifications of the objective and eyepiece lenses:

M = M1 x M2

Substituting the values of M1 and M2 in the above equation, we get:

M = (-v1/u) x (-v2/f) = v1v2/(uf)

From the similar triangles OAF and OED, we can write:

v1/u = FD/FE

v2/f = OA/OB

Substituting these values, we get:

M = (FD/FE) x (OA/OB)

This equation shows that the magnification of the compound microscope depends on the focal lengths of the objective and eyepiece lenses and their distances from the object and the observer's eye.

#SPJ3

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