Math, asked by swanandi01, 1 month ago

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Answered by itzPapaKaHelicopter
4

\huge \fbox \green{❤Solution:}

Given: In The Give figure, BA || ED and BC || EF

\sf \colorbox{pink} {To Prove: }

∠ABC =  ∠DEF

\sf \colorbox{skyblue} {This step is in the pick above}

\sf \colorbox{pink} {Construction:}

Through the points E and B Draw a transversal line T both .

Proof: \:   AB || DE \:  \:  \:  \:  \:  \:  \:  \:  \:   \:    \:  \:  \:  \:   [Given]

So,  \:  \:  \:  \:  \:  \: \:  \:  \:  \:  \: ∠1 = ∠4 \:  \:   \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: \: ..(i)

 \:  \:  \:   \:  \:  \:  \:  \:  \:  \:  \:  \: \:  \: [Corresponding  \: Angeles]

Also, \:  \:  \:  \:  \:  \:  BC || EF \:  \:  \:  \: \:  \:  \:  \:  \:  \:    \:  \:  \:  \:  \:  [Given]

so, \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: ∠2 = ∠3 \:  \:  \: \:  \:  \:  \:  \:  \:  \:  \:  \:  \:   \:  \:  \:  \:  \:   \:  \: ..(ii)

 \:  \:  \:   \:  \:  \:  \:  \:  \:  \:  \:  \: \:  \: [Corresponding  \: Angeles]

Adding  \: (i)  \: and \:  (ii)

we get

∠1 + ∠2 = ∠3 + ∠4

ㅤㅤㅤㅤㅤㅤㅤㅤㅤOR

∠ABC= ∠DEF \:  \:

Hence \:  \:  proved

 \\  \\  \\ \sf \colorbox{gold} {\red(ANSWER ᵇʸ ⁿᵃʷᵃᵇ⁰⁰⁰⁸}

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