Physics, asked by Anonymous, 10 months ago


HELP ME PLZZ .its important

a 15 cm long cube made of oak and side floats in water with 10.5cm of its depth below the surface and its side vertical what is the density of oak.

Answers

Answered by zainab607963
16

Answer:

volume of oak under water = 15*15 * 10.5

so Archimedes says

mass of oak = density of water * volume under water = 1 g/cm^3 * 15*15 * 10.5

total volume of oak = 15*15*15

density = mass/volume = 1 g/cm^3 * 10.5/15

Answered by surendardun30
16

Answer:

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Explanation:

volume of oak under water = 15*15 * 10.5

so Archimedes says

mass of oak = density of water * volume under water = 1 g/cm^3 * 15*15 * 10.5

total volume of oak = 15*15*15

density = mass/volume = 1 g/cm^3 * 10.5/15

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