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a 15 cm long cube made of oak and side floats in water with 10.5cm of its depth below the surface and its side vertical what is the density of oak.
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Answered by
16
Answer:
volume of oak under water = 15*15 * 10.5
so Archimedes says
mass of oak = density of water * volume under water = 1 g/cm^3 * 15*15 * 10.5
total volume of oak = 15*15*15
density = mass/volume = 1 g/cm^3 * 10.5/15
Answered by
16
Answer:
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Explanation:
volume of oak under water = 15*15 * 10.5
so Archimedes says
mass of oak = density of water * volume under water = 1 g/cm^3 * 15*15 * 10.5
total volume of oak = 15*15*15
density = mass/volume = 1 g/cm^3 * 10.5/15
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