help me plzzz fast ..........
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Step-by-step explanation:
=> 6,p,q,18 are in AP
=> 2p = 6+q ........@1
=> 2q = p+18 .......@2
=> multiply @1*2 + @2
=> 4p+2q = 12+2q + p+18
=> 4p-p+(2q-2q) =12+18
=> 3p = 30
=> p=10
=> q = (p+18)/2
=> q = (10+18)/2
=> q = 14.
then AP = 6,10,14,18...
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hii
your answer.....
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