Question

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question 13​

Answer 1

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Answer 2

Answer:

Step-by-step explanation:

To Prove : CA2 = CB . CD

Given: ∠ADC = ∠BAC

Proof: Now In ΔADC and ΔBAC,

∠ADC = ∠BAC

∠ACD = ∠BCA (Common angle)

According to AA similarity, if two corresponding angles of two triangles are equal then the triangles are similar

ΔADC ~ΔBAC (By AA similarity)

We know that corresponding sides of similar triangles are in proportion

Hence in ΔADC and ΔBAC

CA/CB = CD/CA

CA^2 = CB.CA

Hence proved

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