Question

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Q) 【Evaluation 】
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Answer 1

Answer:

13.

Identities used :

${a}^{ - m} = {( \frac{1}{a} )}^{m}$

Step-by-step explanation:

${( {2}^{2} )}^{0} + {2}^{ - 4} \div {2}^{ - 6} + {( \frac{1}{2} )}^{ - 3} \\ \\ = {4}^{0} + {( \frac{1}{2} )}^{4} \div {( \frac{1}{2} )}^{6} + {( \frac{2}{1} )}^{3} \\ \\ = 1 + \frac{ {1}^{4} }{ {2}^{4} } \div \frac{ {1}^{6} }{ {2}^{6} } + {2}^{3} \\ \\ = 1 + \frac{1}{16} \div \frac{1}{64} + 8 \\ \\ = 1 + \frac{1}{16} \times 64 + 8$

According to BODMAS:

$= 1 + 4 + 8 \\ \\ \bf = 13$