Question

HELP ME QUESTION IN THE ATTACHMENT​

Answer 1

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

Question is little bit complicated but I will try my best to solve it. Hope this will help you!!

It is mentioned that the inner circumference of the track is 352 m.

let the inner circumference be 2πr.

therefore,

2πr= 352m

2*22/7*r=352

r=56m------(1)

Also outer circumference of the track is 392 m.

let the outer circumference be 2πr'.

therefore,

2πr'= 396m

2*22/7*r'= 396

r= 63m--------(2)

Width of the track= r' -r= 63m -56m = 7m

Area of the track= πr'²- πr²= 22/7*(63)²- 22/7*(56)²

Hence, the area of track is 2618 m²