Question

Help me quick please

Answer 1

Answer:

t=2 is the correct answer Mark me brainliest.

Answer 2

Step-by-step explanation:

ZBCD = 2CDE = <DEB = EBC = 90°

C, ZACD and <DCF from a linear pair

then

=> ZACD + 2DCF =180°

=> <BCA +<BCD+2DCF= 180°

=> <BCA+90° +2DCF =180° => <BCA +2DCF= 90°

=> <BCA + BCA-90° [2BCA =<DCF]

=> 22BCA =90°

=> ZBCA = 90%2 = 45°

ABAC we have

cos BCA =

=> cos 45° = AC/BC

=>

=> BC =6cm

=>A DFC =

=> cos 45° = CF/CD

=>

Let BD be the diagonal of rectangular

BCDE

ABCD we have

=> BD = BC + CD

(By phytagoras theorem) => BD= (6)+(12)

=> 72+288 = 360

=> BD = 360

=> BD = 6 cm