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Answered by
0
Answer:
27
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Answered by
0
Answer:
9
Step-by-step explanation:
numerator;
(3^5)^(n/5)×3^(2n+1)= 3^(5n/5)×3^(2n+1)
= 3^n×3^(2n+1)
=3^(3n+1)
denominator;
[3^2n]×[3^(n-1)]=3^(3n-1)
numerator/ denominator = 3^(3n+1) / 3^(3n-1)
= 3^ ( 3n+1 -3n+1 )
= 3 ^ 2
= 9
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