Question

help me read the problem and follow the instructions​

Answer 1

Answer:

answer for the given problem is given

Answer 2

Solution :-

Let cost of small box of orange be Php 'x' and cost of large box of orange be Php 'y'.

Case :- 1.

Malt sell 3 small orange boxes and 14 large orange boxes for total Php 203.

$\bf\implies \:3x + 14y = 203.....(1)$

Case :- 2.

Ming sell 11 small orange boxes and 11 large orange boxes for total Php 220.

$\bf\implies \:11x + 11y = 220$

Divide by 11 both sides, we get

$\bf\implies \:x + y = 20.....(2)$

Now from (2), we get

$\bf\implies \:x = 20 - y.....(3)$

Put (3) in equation (1), we get

$\bf\implies \:3(20 - y) + 14y = 203$

$\bf\implies \:60 - 3y + 14y = 203$

$\bf\implies \:11y = 143$

$\bf\implies \:y = 13$

Put y = 13 in equation (3), we get

$\bf\implies \:x = 7$

$\bf\underbrace\orange{Verification}$

$\bf\implies \:3x + 14y = 203$

$\bf\implies \:3 \times 7 + 14 \times 13 = 203$

$\bf\implies \:21 + 182 = 203$

$\bf\implies \:203 = 203$

$\large{\boxed{\boxed{\bf{Hence, Verified}}}}$