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The sum of two natural numbers is 12, if the sum of their reciprocal is 4\9 find the numbers
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3 and 9
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Given:
The sum of two natural numbers=12
The sum of their reciprocals=4/9
To find:
The two natural numbers
Solution:
We can find the solution by following the steps given below-
Let the two numbers be A and B.
We know that the sum of A and B is 12.
Also, the sum of their reciprocals is 4/9
1/A+1/B=4/9
On taking the LCM,
B+A/AB=4/9
Since A+B= 12, we get
12/AB=4/9
AB=3×9
AB=27
Now, we need to figure out the values of A and B such that their sum is 12 and the product is 27.
So, A can be 3 or 9 and B can be 9 or 3.
Therefore, the two natural numbers are 3 and 9.
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