Question

Help me solve it please​

Answer 1

Answer:

k(2k+5)=3

2k^2+5k=3

2k^2+5k-3=0

2k^2+6k-k-3=0

(2^2+6)+(−−3)=0

2k(k+3)-1(k+3)=0

(2k-1)(k+3)=0

k=1/2,k=-3

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