Math, asked by kirito8, 8 months ago

help me solve the question above ​

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Answered by Nirupamhhadra
2

Answer:

1) x = 2y+2/5

2) 16-2x=3y ok it is your answer. please make me brainliest.

Step-by-step explanation:

1) (32)^x/2^y+1=1

or, (√32)^x=2^y+1

or, (√32)^x=(2^5)^y+1/5

or, (√32)^x=32^y+1/5

or, (√32)^x= (√32)^2y+2/5

or, x=2y+2/5

2) 16^4-(x/2)-8^y= 0

or, 16^4-(x/2)= 8^y

or, 16^ 8-x/2= 8^y

or, (2^4)^8-x/2= (2^3)^y

or, 2^32-4x/2= 2^3y

or, 2^16-2x= 2^3y

or, 16- 2x= 3y

Answered by Divya2385
2

Answer:

Thank u , Thank u so much for yr answer

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