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Solve the question from Ch-19.
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Please solve this question as it is coming in my final exam.
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I hope it will help you
Step-by-step explanation:
i)
mean = \frac{18 + 20 + 21 + 23 + 25 + 25 + 29 + 31 + 31 + 37}{10}mean=
10
18+20+21+23+25+25+29+31+31+37
=260÷10
=26
ii) Mean time is 26. So, 3 students took more time than the mean (31,31,37).
iii) If the student who took 37 minutes had taken 23 minutes then the times would be:
18,20,21,23,23,25,25,26,31,31
So mean would be 246÷10=24.6
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