Help me solve this..
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Heya ✌✌Here is u r Ans ➡➡➡
⭐⭐⭐⭐⭐⭐⭐⭐⭐⭐⭐⭐⭐⭐
Apply principle of conservation of momentum and energy
Momentum before collision = momentum after collision
0.1u + m*0 = 0.1*0 + m*3
½*0.1*u2 = ½*m*32
Solving these two equations, u = 3
½kx2 = ½k(x/2)2 + ½*0.1*32
3/4 kx2 = 0.9
½kx2 = 0.6 J
The correct option is B.
⭐⭐⭐⭐⭐⭐⭐⭐⭐⭐⭐⭐⭐⭐
Hope This Helps u ☺
⭐⭐⭐⭐⭐⭐⭐⭐⭐⭐⭐⭐⭐⭐
Apply principle of conservation of momentum and energy
Momentum before collision = momentum after collision
0.1u + m*0 = 0.1*0 + m*3
½*0.1*u2 = ½*m*32
Solving these two equations, u = 3
½kx2 = ½k(x/2)2 + ½*0.1*32
3/4 kx2 = 0.9
½kx2 = 0.6 J
The correct option is B.
⭐⭐⭐⭐⭐⭐⭐⭐⭐⭐⭐⭐⭐⭐
Hope This Helps u ☺
Answered by
0
yup..................no
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