Question

Help me solve this equations
$\frac{3[p+8]}{1}$ =$\frac{-6[p+6]}{-3}$

Answer 1

Answer:

3(p+8) *-3=-6(p+6)

3p+24*-3=6p+36

3p+32=6p+36

3p-6p=36-32

-3p=4

p=-3/4

I THINK THIS ANSWER IS CORRECT.

THANK YOU

Answer 2

ACCORDING TO QUESTION:

$\frac{3[p+8]}{1} =\frac{-6[p+6]}{-3} \:$

on cross multiplication:

$- 3(3(p + 8) = - 6(p + 6)$

$- 3(3(p + 8) = - 6(p + 6) \\ - 9(p + 8) = - 6(p + 6) \\ - 9p - 72 = - 6p + 36$

on solving furthermore by equating there values,

$- 9p + 6p = 36 + 72 \\ - 3p = 108 \\ p = - \frac{108}{3} \\ p = - 36$

so the value of p is -36