Question

Help me solve this question ​

Answer 1

$\huge\colorbox{white}{ \colorbox{white}{\colorbox{white}{Question}}}$

$\tt \: \ (625)^{x-1} = \ (0.008)^3-x$

$\huge\colorbox{white}{ \colorbox{white}{\colorbox{white}{Answer}}}$

Given:

$\tt \: \ (625)^{x-1} = \ (0.008)^3-x$

To Find :-

$\color{green} {Value\: of \:. x \: = \: ?}$

Solution :-

$\sf\huge\implies$$\tt \: x = \625^ {x-1}$

$\sf\huge\implies$$\tt\: x + 1 = 625 x$

$\sf\huge\implies$$\tt \: \ frac{x + 1}{625} = x$

$\sf\huge\implies$ $\tt \: \0.008 ^ {3 - x}$

$\sf\huge\implies$$\tt\: 0.024 -x$

$\sf\huge\implies$ $\tt \: 625 x + x =. 0.024 + 1$

$\sf\huge\implies$$\tt \: 625x = 1.024$

$\sf\huge\implies$$\tt \: \frac {1.204}{626}$

$\sf\huge\implies$ $\tt \: \frac {1024}{1000} × \frac {1}{626}$

$\sf\huge\implies$ 0.001 approx

Hope it helps you :)