help me solve this question please
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Hii its tom85
y= sin(2πt+π/6)
y=(sqrt3/2)*sin2πt+cos2πt(1/2)
differentiating with respect to t we get
dy/dt=1/2(2πsqrt3cos2πt -π sin2πt)
dy/dt=π/2(2sqrt3cos2πt - sin2πt)
___________/\___________☺️
hope it helps you dude
engineer420:
thnx for your help
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