Math, asked by dkanishka01, 10 months ago

Help me solve this trigonometric problem

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Answers

Answered by roshankr1000
2

Answer:

cotAcosA/cotA+cosA

=[(cosA/sinA)cosA]/[(cosA/sinA)+cosA]

=(cos²A/sinA)/[(cosA+sinAcosA)/sinA]

=cos²A/cosA(1+sinA)

=cosA/(1+sinA)

=[cosA(1-sinA)]/[(1+sinA)(1-sinA)]

[multiplying the numerator and the denominator with (1-sinA)]

=[cosA(1-sinA)]/(1-sin²A)

=(cosA-cosAsinA)/cos²A

=[(cosA-cosAsinA)/sinA]/(cos²A/sinA)

[dividing the numerator and the denominator by sinA]

=[(cosA/sinA)-(cosAsinA/sinA)]/(cosA/sinA)cosA

=(cotA-cosA)/cotAcosA

Hope so it will help:))

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roshankr1000: Please mark it as brainliest :))
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