Question

help me solvin 11th question​

Answer 1

I don't know the answer

Answer 2

WKT sum of all angles of a triangle=180°

Given,angle A=80°

so sum of angle B & C=180-80=100°

As the bisector divides the angle B &C by half ,we have

new sum of angles formed at B & C after bisect=100/2=50°

i.e.

sum of angle OBC and angle OBC=50°

So angle BOC=180-50=130°.