help me solving this 3rd question
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Thn q
Thn q
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0.4 x + 0.3 y =1.7
0.7 x - 0.2 y =0.8
on removing the decimals , we get
4/10x + 3/10y =17/10
7/10x - 2/10y =8/10
4x +3y =17/10 X 10
7x - 2y =8/10 X10
THEREFORE,
4x + 3y =17[x2]
7x - 2y =8 [x3]
⇒8x + 6y =34
21x -6y=24
⇒29x =58
x=58/29
⇒x=2
putting this value of x in any one of the equations,we get
7x -2y=8
7[2]-2y=8
14-2y=8
-2y=8-14
-2y=-6
y=-6/-2
y=3
therefore,
x=2,y=3
hope it helps you!!!
0.7 x - 0.2 y =0.8
on removing the decimals , we get
4/10x + 3/10y =17/10
7/10x - 2/10y =8/10
4x +3y =17/10 X 10
7x - 2y =8/10 X10
THEREFORE,
4x + 3y =17[x2]
7x - 2y =8 [x3]
⇒8x + 6y =34
21x -6y=24
⇒29x =58
x=58/29
⇒x=2
putting this value of x in any one of the equations,we get
7x -2y=8
7[2]-2y=8
14-2y=8
-2y=8-14
-2y=-6
y=-6/-2
y=3
therefore,
x=2,y=3
hope it helps you!!!
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