Math, asked by rikeshrai, 10 months ago

help me solving this algebric quesrion​

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Answered by Ayushp08
1

Answer:

Let the multiples be x, x+3 and x+6

Now, according to the question----

x + x+3 + x+6 = 333

3x + 9 = 333

3x = 333-9

x = 324÷3

x = 108

Therefore the required numbers are 18, 108+3=111 & 108+6 = 114


rikeshrai: bro the answer is 108,111,114
rikeshrai: it's ok I get the right answer
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