help me solving this algebric quesrion
Attachments:
Answers
Answered by
1
Answer:
Let the multiples be x, x+3 and x+6
Now, according to the question----
x + x+3 + x+6 = 333
3x + 9 = 333
3x = 333-9
x = 324÷3
x = 108
Therefore the required numbers are 18, 108+3=111 & 108+6 = 114
rikeshrai:
bro the answer is 108,111,114
Similar questions