Math, asked by Anonymous, 2 months ago

help me solving this Question....

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Answered by pradeepa13
2

Answer:

a= -16/103, b= -15/103

Step-by-step explanation:

3+√7/ 3-4√7

By rationalising the denominator,

(3+√7)(3+4√7) / (3-4√7)(3+4√7)

= 9 + 12√7 +3√7+ 7 / 9- 112

= 16+15√7 / -103

=-16/103 - 15√7/103

On comparing with a+b√7, we get

a= -16/103

b= -15/103

Hope it helps!

Answered by MOSFET01
2

Answer:

Above image is having step by step solution

Answer of this question is a = - 37/103 & b = - 15/103

1.  \dfrac{3\:+\:\sqrt{7}}{3\:-\:4\sqrt{7}}

Rationalise numerator and denominator and multiply it with

(3\:+\:4\sqrt{7})

Step 1

 \dfrac{3\:+\:\sqrt{7}}{3\:-\:4\sqrt{7}}\times\dfrac{3\:+\:4\sqrt{7}}{3\:+\:4\sqrt{7}}

Step 2

 \dfrac{(3\:+\:\sqrt{7})(3\:+\:4\sqrt{7})}{(3)^{2}-(4\sqrt{7})^{2}}

Step 3

Simplification

 \dfrac{9\:+\:12\sqrt{7}\:+\:3\sqrt{7}\:+\:28}{9\:-\:112}

Step 4

 \dfrac{37\:+\:15\sqrt{7}}{-103}

Compare LHS & RHS

 \dfrac{37\:+\:15\sqrt{7}}{-103}\: =\: a\:+\:b\sqrt{7}

Answer

 a\:=\:-\dfrac{37}{103}

 b\:=\:-\dfrac{15\sqrt{7}}{103}

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