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please give me book name and your class
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Answer:
T=100/7s,r=12cm
ω=2πT=(2×22/7(100/7)
=0.44rad/s
,v=rω12×0.44
=5.3cms−1
sorry I can't draw graph here.
Explanation:
Her,<br> (a) Angular speed ,ltbrltgt<br> Linear speed,<br><br> (b) The given motion is a uniform circular motion. Here the direction of velocity id along the tangent to the circle at every point. The acceleration in this motion is centripetal acceleration. It is alwys directed towards the centre of the circle. Since this direction changes therfore, the acceleration here is not a constant vector. The magnitude of acceleration is_(c) =omega ^(2) =(0.44 )^(2) xx 12 2.3 cm s^(2)
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