Question

help me to answer it guys​

Answer 1

5). Let ABCD be a trapezium with,

AB || CD

AB=25m

CD=10m

BC=14m

AD=13m

Draw CE || DA. So, ADCE is a parallelogram with,

CD=AE=10m

CE=AD=13m

BE=AB−AE=25−10=15m

In ΔBCE, the semi perimeter will be,

s= a+b+c

2

s= 14+13+15

2

s=21m.

Area of ΔBCE,

A= s√(s−a)(s−b)(s−c)

= 21√(21−14)(21−13)(21−15)

= 21 √(7)(8)(6)

= √7056

= 84m²

Also, area of ΔBCE is,

A= 1/2 × base × height

84= 1/2 × 15 × CL

84 ×2 = CL

15

Therefore, CL = 56

5

Now, the area of trapezium is,

A= 1/2 (sumofparallelsides)(height)

A= 1/2 × (25+10) (56)

5

A = 196m²

Therefore, the area of the trapezium is 196m².