Help me to do question 9
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since it is given that it is isosceles triangle
so AC=CB
by Pythagorean triplet we have
AB^2 = AC^2+CB^2
AB^2 = AC^2+AC^2
AB^2 = 2AC^2
hence proved
so AC=CB
by Pythagorean triplet we have
AB^2 = AC^2+CB^2
AB^2 = AC^2+AC^2
AB^2 = 2AC^2
hence proved
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Hope this helps you....
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