Question

help me to evalute this thing​

Answer 1

Step-by-step explanation:

We have,

$\int \frac{1}{1 + \frac{ {x}^{2} }{4} } dx$

$= \int \frac{4}{4 + {x}^{2} } dx$

$= 4 \int \frac{dx}{(2)^{2} + {(x)}^{2} }$

$= 4 \times \frac{1}{2} \tan^{ - 1} ( \frac{x}{2} ) + c$

$= 2 \tan^{ - 1} ( \frac{x}{2} ) + c$