help me to find answer of this question
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Answered by
3
Step-by-step explanation:
Given equation,
(1 + m²)x² + 2mcx + ( c² - a² ) =0
On comparing with ax² + bx + c = 0,
a = (1 + m²), b = 2m, c = (c² - a²)
For equal roots,
b² - 4ac = 0
⇒ 4m²c² = 4( 1 + m² ) ( c² - a² )
⇒ 4m²c² = 4c² - 4a² + 4c²m² - 4a²m²
⇒ 4c² - 4a²m² - 4a² = 0
⇒ 4 [ c² - a²m² - a² ] = 0
⇒ c² = a²m² + a²
⇒ c² = a² [1 + m²]
Hope it helps!
Answered by
20
Answer:
hey friend,
the above question is from oswal sample paper.
but the question is misprint.
it would be 2mcx in place of 2mx
.
you can see the correct question in R s Agarwal book .
Step-by-step explanation:
for correct solution refer to the above attachment.
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