Question

help me to find answer of this question​

Answer 1

Step-by-step explanation:

Given equation,

(1 + m²)x² + 2mcx + ( c² - a² ) =0

On comparing with ax² + bx + c = 0,

a = (1 + m²), b = 2m, c = (c² - a²)

For equal roots,

b² - 4ac = 0

⇒ 4m²c² = 4( 1 + m² ) ( c² - a² )

⇒ 4m²c² = 4c² - 4a² + 4c²m² - 4a²m²

⇒ 4c² - 4a²m² - 4a² = 0

⇒ 4 [ c² - a²m² - a² ] = 0

⇒ c² = a²m² + a²

⇒ c² = a² [1 + m²] 

Hope it helps!

Answer 2

Answer:

hey friend,

the above question is from oswal sample paper.

but the question is misprint.

it would be 2mcx in place of 2mx

.

you can see the correct question in R s Agarwal book .

Step-by-step explanation:

for correct solution refer to the above attachment.