help me to find out the oxidation number
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(NH₄)₂[CoF₄]
2(+1) + x + 4(-1) = 0
2 + x - 4 = 0
x - 2 = 0
x = +2
Therefore the oxidation state of Cobalt is +2
2(+1) + x + 4(-1) = 0
2 + x - 4 = 0
x - 2 = 0
x = +2
Therefore the oxidation state of Cobalt is +2
JUSTASTUDENT2:
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what is the co-ordination number of that question
coordination number is the number of atoms present in the coorination sphere(those square brackets).....which in this case is 4
leaving the central atom of course
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