help me to find out the questions of simple interest nd compound interest
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1) We know that A = P(1+r/100)^n
Given that P = 1250, n = 3 months. and r is decreased by 20%.
A = 1250(1 - 20/100)^3
= 1250(80/100)^3
= 1250(4/5)^3
= 1250(64/125)
= 640.
The number of stray dogs in the city = 640.
2) Present new value of the machine t=750
Rate of depreciation=-10 ( Negative sign of rate indicates the depreciation)
time (n) =2 year
the value of machine =750*(1-10/100)*2
=750*90/100?-90/100=607.50.
3) ans in attached image
Amount is Rs. 12734.49
Compound Interest is Rs. 734.49
I hope it help you
Given that P = 1250, n = 3 months. and r is decreased by 20%.
A = 1250(1 - 20/100)^3
= 1250(80/100)^3
= 1250(4/5)^3
= 1250(64/125)
= 640.
The number of stray dogs in the city = 640.
2) Present new value of the machine t=750
Rate of depreciation=-10 ( Negative sign of rate indicates the depreciation)
time (n) =2 year
the value of machine =750*(1-10/100)*2
=750*90/100?-90/100=607.50.
3) ans in attached image
Amount is Rs. 12734.49
Compound Interest is Rs. 734.49
I hope it help you
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